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7=4x^2-12x
We move all terms to the left:
7-(4x^2-12x)=0
We get rid of parentheses
-4x^2+12x+7=0
a = -4; b = 12; c = +7;
Δ = b2-4ac
Δ = 122-4·(-4)·7
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-16}{2*-4}=\frac{-28}{-8} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+16}{2*-4}=\frac{4}{-8} =-1/2 $
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